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2x^2+108x-360=0
a = 2; b = 108; c = -360;
Δ = b2-4ac
Δ = 1082-4·2·(-360)
Δ = 14544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{14544}=\sqrt{144*101}=\sqrt{144}*\sqrt{101}=12\sqrt{101}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(108)-12\sqrt{101}}{2*2}=\frac{-108-12\sqrt{101}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(108)+12\sqrt{101}}{2*2}=\frac{-108+12\sqrt{101}}{4} $
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